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RT @BlackPhysicists: $$\Lambda _b$$ Λ b decays into $$\Lambda _c^*\ell \bar{\nu }_\ell $$ Λ c ∗ ℓ ν ¯ ℓ and $$\Lambda _c^*\pi ^-$$ Λ c ∗ π…
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$$\Lambda _b$$ Λ b decays into $$\Lambda _c^*\ell \bar{\nu }_\ell $$ Λ c ∗ ℓ ν ¯ ℓ and $$\Lambda _c^*\pi ^-$$ Λ c ∗ π - $$[\Lambda _c^*=\Lambda _c(2595)$$ [ Λ c ∗ = Λ c https://t.co/WhQagwH7DQ via @SpringerPhysics https://t.co/GnVLqgM1Ze